7th Contest of Newbies

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7th Contest of Newbies

Postby Observer » Fri Dec 02, 2011 6:38 pm

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7th Contest of Newbies
Date: December 31st, 2011 (Saturday)
Time: 12:00 - 16:00 (UTC)
URL: http://uva.onlinejudge.org

Hello, everyone! We are happy to announce that the 7th Contest of Newbies is to be held on UVa Online Judge on the last day of 2011. I would say it is one of the best ways to celebrate the coming of new year. :)

As in the previous contest, three tasks are considered "easy" and solvable even by new programmers.

For a taste of what our problems are like, here are some highlights of our old tasks:

Easier:
10976 - Fractions Again?!
11152 - Colourful Flowers

Harder:
10817 - Headmaster's Headache
11374 - Airport Express
11570 - Sudoku without numbers?
11914 - An Amazing Race

We look forward to your participation and support. You are of course welcome to promote this contest to your friends~

[EDIT] For Facebook users:
http://www.facebook.com/events/204195869660292/
7th Contest of Newbies
Date: December 31st, 2011 (Saturday)
Time: 12:00 - 16:00 (UTC)
URL: http://uva.onlinejudge.org
Observer
Guru
 
Posts: 570
Joined: Sat May 10, 2003 4:20 am
Location: Hong Kong

Re: 7th Contest of Newbies

Postby Observer » Sat Dec 31, 2011 8:16 pm

Special thanks to the 100+ teams who took part in the 7th Contest of Newbies! The six problems are now available on the 24h Online Judge, with number 12397-12402.

For your reference, here are the last-hour hints (slightly modified) given on the clarification board:
"
A-C are easier - just go the simple way.

A. You can find Roman conversion codes via Wiki.
B. Do increment instead of decrement.
C. Some brute-force method works!
-------------------------------------------
D. Can you solve it with N=M=K?
E. Consider Fibonacci numbers.
F. Judge solution uses a search and has more than 200 lines.
"
7th Contest of Newbies
Date: December 31st, 2011 (Saturday)
Time: 12:00 - 16:00 (UTC)
URL: http://uva.onlinejudge.org
Observer
Guru
 
Posts: 570
Joined: Sat May 10, 2003 4:20 am
Location: Hong Kong


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