Problem I
Back to Kernighan-Ritchie
Input: Standard Input
Output: Standard Output

You must have heard the name of Kernighan and Ritchie, the authors of The C Programming Language. While coding in C, we use different control statements and loops, such as, if-then-else, for, do-while, etc. Consider the following fragment of pseudo code:
//execution starts here
do {
U;
V;
} while(condition);
W;
In the above code, there is a bias in each conditional branch. Such codes can be represented by control flow graphs like below:

Let the probability of jumping from one node of the graph to any of its adjacent nodes be equal. So, in the above code fragment, the expected number of times U executes is 2. In this problem, you will be given with such a control flow graph and find the expected number of times a node is visited starting from a specific node.
Input
Input consists of several test cases. There will be maximum 100 test cases. Each case starts with an integer: n (n ≤ 100). Here n is the number of nodes in the graph. Each node in the graph is labeled with 1 to n and execution always starts from 1. Each of the next few lines has two integers: start and end which means execution may jump from node start to node end. A value of zero for start ends this list. After this, there will be an integer q (q ≤ 100) denoting the number of queries to come. Next q lines contain a node number for which you have to evaluate the expected number of times the node is visited. The last test case has value of zero for n which should not be processed.
Output for each test case should start with “Case #i:” with next q lines containing the results of the queries in the input with three decimal places. There can be situations where a node will be visited forever (for example, an infinite for loop). In such cases, you should print “infinity” (without the quotes). See the sample output section for details of formatting.
|
3 1 2 2 3 2 1 0 0 3 1 2 3 3 1 2 2 3 3 1 0 0 3 3 2 1 0 |
Case
#1: 2.000 2.000 1.000 Case
#2: infinity infinity infinity |
Problem setter: Mohammad Sajjad Hossain
Special Thanks: Shahriar Manzoor